所以目标函数为: Min Z=>12KiZi+>(0.5Fil+0.6Fi2) =1 +∑[240+240(7-1)N+∑360×501 约束条件为 400∑X7+Fil=∑Rl 400>Xi=116000 240>Y+Fi2 R2t 240∑Y=79200 X1+Y1+1=50 St X2+Y2+H1+W2=50 x+Y+W-1+W=50+∑Nt Zi<50 8=0 Ni=50 Ni≤3 Xiyiziwi. Ni Fli F2i.>o所以目标函数为： Min z = 约束条件为：     = = = = + + − +  + + 7 1 7 1 7 1 7 1 [240 240(7 )] 360 50 12 (0.5 1 0.6 2) i i i i i Ni i KiZi Fi Fi , , , , , 1 , 2 , 0 3 50 8 0 50 1 50 2 2 1 2 50 1 1 1 50 240 79200 240 2 2 400 116000 400 1 1 7 1 2 1 8 1 1 1 8 1 1 1   = =  + + − + = + + + + = + + = = + = = + =         = − = = = = = = = Xi Yi Zi Wi Ni F i F i K Ni W Ni W Zi Xi Yi Wi Wi Nt X Y W W X Y W Yi Yt Fi R t Xi Xi Fi R t i i t i i t i t i i t i t St