因此，开=4P(X2+Y2≤1)≈4#{x2+2≤1}/m. ·n=1000,元=3.168 ●n=100.000,元=3.14312. ●n=107,元=3.141356. Previous Next First Last Back Forward 2œd, π = 4P(X2 + Y 2 ≤ 1) ≈ 4#{x 2 + y 2 ≤ 1}/n. • n = 1000, ˆπ = 3.168. • n = 100, 000, ˆπ = 3.14312. • n = 107 , ˆπ = 3.141356. Previous Next First Last Back Forward 2