do 1+x2dx≈1.147 d1=「xl+x2dx≈0609 得方程组 2 1.147 0.609 解 出 Co=0.934,a1=0.426 故 S1(x)=0.934+0.426x 平方误差 S|2=(/,)-(S:f)=(,)-∑a(1 2 0 0 d x x = + 1 d 1.147, 1 2 1 0 d x x x = + 1 d 0.609 得方程组 = 0.609 1.147 3 1 2 1 2 1 1 1 0 a a , 解 出 a0 = 0.934, a1 = 0.426 , 故 ( ) 0.934 0.426 . * 1 S x = + x 平方误差 2 * 2 1 0 ( , ) ( , ) ( , ) ( , ) n k k k f f S f f f a f = = − = −