后调子大学 Shihezi University 考虑sp附近，AgC溶解进入溶液的离子： -0.1%: [CH=[C]剩余+[C]溶解 [C】溶解[Ag]=C Kp=[C]IAg]=(IC]剩余+c)c c=2.9×106molL, pC1=4.28, pAg=pKp-pCl=9.81-4.28=5.53考虑sp附近，AgCl溶解进入溶液的离子： 溶解进入溶液的离子： -0.1%： [Cl -] =[Cl -]剩余+[Cl -]溶解 [Cl -]溶解=[Ag++ ]=c Kspsp=[Cl -][Ag++ ]=([Cl -]剩余+ c) c c= 2.9 × 10-6-6 mol/L, pCl = 4.28, = 4.28, = 4.28, = 4.28, = 4.28, = 4.28, = 4.28, = 4.28, pAg = pKspsp - pCl = 9.81 - 4.28 = 5.53 = 9.81 - 4.28 = 5.53 = 9.81 - 4.28 = 5.53 = 9.81 - 4.28 = 5.53 = 9.81 - 4.28 = 5.53 = 9.81 - 4.28 = 5.53 = 9.81 - 4.28 = 5.53 = 9.81 - 4.28 = 5.53