2、求H(iO) H(j0)=-2 RC r+ JOC×1 RO C 1 H(jO) RO atO H(O)如图3.10-6所示 H() 0 图3.10-6     j H j RC + = ( ) = 1 令 2、求H( j) 1 2 2 ( ) Z Z Z H j +  = RC j RC j C R j C 1 1 1 1 + = + =    H()如图3.10−6所示 0  H() 图3.10-6