电机学学习指导 第五章感应电机 在U1=380V,f=50Hz时 3×2x(380√3 2x×50+1)+63+3 =17.34(Nm) 3×2×(83) =5695(Nm) 4x×50×1+y2+(35+35 =0.1239 12+(35+3.5 在U1=190V,=25Hz时(注意X1∝f、X2a∝f1) 3×2×90/3×1 (3.535)272829(Nm) 2×25 (1+1) 3×2x[190 =49.53(Nm) 3.53.5 4丌×25×1+,12+ 0.2155 53.5 (2)不考虑定子电阻时 m,p UuR 2丌R2+(X1 Tm s miP. U1 R? 4f, Xia+X, X+X 在U1=380V,f=50Hz时 =3×2×(313×1 2z×50×p2+(35+35) =1839(Nm) 3×2×B80/3 =6566(N·m) 4z×50×(35+35 =0.1429 3.5+3.5 在U1=190V,f=25Hz时电机学学习指导 第五章 感应电机 在 U1=380V，f1=50Hz 时 ( ) [( ) ( ) ] 17.34(N m) 2 50 1 1 3.5 3.5 3 2 380 3 1 2 2 2 = ⋅ × × + + + × × × = π Tst ( ) ( ) 56.95(N m) 4 50 1 1 3.5 3.5 3 2 380 3 2 2 2 max = ⋅     × × + + + × × = π T ( ) 0.1239 1 1 3.5 3.5 1 2 2 = + + + sm = 在 U1=190V，f1=25Hz 时（注意 X1σ ∝ f1、 2 1 X ′ ∝ f σ ） ( ) ( ) 28.29(N m) 2 3.5 2 3.5 2 25 1 1 3 2 190 3 1 2 2 2 = ⋅               × × + + + × × × ′ = π Tst ( ) 49.53(N m) 2 3.5 2 3.5 4 25 1 1 3 2 190 3 2 2 2 max = ⋅               × × + + + × × ′ = π T 0.2155 2 3.5 2 3.5 1 1 1 2 2 =       + + + sm ′ = （2）不考虑定子电阻时 ( )2 1 2 2 2 2 2 1 1 1 2 σ σ φ π R X X U R f m p Tst ′ + + ′ ′ ≈ ⋅ σ σ φ π 1 2 2 1 1 1 max 4 X X U f m p T + ′ ≈ ⋅ 1σ 2σ 2 X X R sm + ′ ′ ≈ 在 U1=380V，f1=50Hz 时 ( ) [ ( ) ] 18.39(N m) 2 50 1 3.5 3.5 3 2 380 3 1 2 2 2 = ⋅ × × + + × × × = π Tst ( ) ( ) 65.66(N m) 4 50 3.5 3.5 3 2 380 3 2 max = ⋅ × × + × × = π T 0.1429 3.5 3.5 1 = + sm = 在 U1=190V，f1=25Hz 时 -40-