轴向力 Fa2-FttanB-2039X tan922-336N 齿轮3圆周力Ft3=200072/d3=2000×500/122034=8194N 径向力F3= Ftatanan/cos=8194×tan20°cos10°2831=3033N 轴向力 Fa= FutanG3=8194×tan10°2833=1515N 2)中间轴的受力图: Frs ma2 垂直面受力简图 Ft2 a)同轴式 b)展开式 3)计算轴承反力 同轴式减速器: RAH=Fr3 (L2+L3 ) Fr2L3+Ma3-Ma2/(L1+L2+L3) Ja2=Fa2d2/2=336×490.54/2=824l1Nmm Ma3=Fad32=1515×122.034/2=9244lNmm 若RAH=(3033×2L+752L+92441-82411)/3L=2303N RBH=Fr+Fr2-RAH=752+3033-2303=1482N RvH=(Ft×2L-F2L/3L=(8194×2L-2039Ly3L=4783N RBv=Ft3-Ft2-RN=819420394783=1372N A轴承的反力FBA=VRin+Rn=√23032+473508N 轴承的反力FRB=√R2+R2y=14822+13722=2020N 展开式减速器 RAH=(Fr3*2L+Ma2+Mas-Fr2*L)/3L =3033×2L+92441+82411-752L/3L=235lN RBH=RAH-F3+Fa=2354-3033+752=72N RAv=(Ft*2L+Fn2*L3L=(2×8194+2039)/3=6142N轴向力 Fa2=Ft2tan=2039×tan9°22′=336N 齿轮 3 圆周力 Ft3=2000T2/d3=2000×500/122.034=8194N 径向力 Fr3=Ft3tann/cos=8194×tan20°/cos10°28′31′′=3033N 轴向力 Fa3=Ft3tan3=8194×tan 10°28′33′′=1515N 2）中间轴的受力图： a)同轴式 b)展开式 3）计算轴承反力 同轴式减速器： RAH=Fr3(L2+L3)+Fr2L3+Ma3-Ma2/(L1+L2+L3) Ma2=Fa2d2/2=336×490.54/2=82411N·mm Ma3=Fa3d3/2=1515×122.034/2=92441N·mm 若 RAH=(3033×2L+752L+92441-82411)/3L=2303N RBH=Fr3+Fr2-RAH=752+3033-2303=1482N RVH=(Ft3×2L-Ft2L)/3L=(8194×2L-2039L)/3L=4783N RBV=Ft3-Ft2-RAV=8194-2039-4783=1372N A 轴承的反力 FRA= 2 2 RAH + RAV = 2 2 2303 + 4783 =5308N B 轴承的反力 FRB= 2 2 RBH + RBV = 2 2 1482 +1372 =2020N 展开式减速器 RAH=(Fr3*2L+Ma2+Ma3-Fr2*L)/3L =3033×2L+92441+82411-752L/3L=2351N RBH=RAH-Fr3+ Fr2=2354-3033+752=72N RAV=(Ft3*2L+ Fr2*L)/3L=(2×8194+2039)/3=6142N