3 0 678 8 3 10 Stata数据为: 12 2345678 7 6 10 10 11 1.建立检验假设,确定检验水准 H0:=0,两种药物治疗的冻疮痊愈平均时间相同 H:μ≠0,两种药物治疗的冻疮痊愈平均时间不同 Stata命令为: ttest x1 结果为 Paired t test Variable Mean Std. Err. Std. Dev. [95% Conf. Intervall 7.875 76619422.1671246.0632399.686761 888 7071068 28.327958 11.67204 diff I 2.1251.0763283.044316-4.6701114201115 mean (diff)= mean(x1-x2) t=-1.9743 Ho: mean(diff)=0 degrees of freed3 6 9 3 4 4 12 8 5 7 6 -1 6 10 10 0 7 8 11 3 8 10 11 1 Stata 数据为： x1 x2 1 8 12 2 10 9 3 6 9 4 4 12 5 7 6 6 10 10 7 8 11 8 10 11 1.建立检验假设，确定检验水准 H0： d = 0 ，两种药物治疗的冻疮痊愈平均时间相同 H1：d  0 ，两种药物治疗的冻疮痊愈平均时间不同  = 0.05 Stata 命令为： ttest x1= x2 结果为： Paired t test ------------------------------------------------------------------------------ Variable | Obs Mean Std. Err. Std. Dev. [95% Conf. Interval] ---------+-------------------------------------------------------------------- x1 | 8 7.875 .7661942 2.167124 6.063239 9.686761 x2 | 8 10 .7071068 2 8.327958 11.67204 ---------+-------------------------------------------------------------------- diff | 8 -2.125 1.076328 3.044316 -4.670111 .4201115 ------------------------------------------------------------------------------ mean(diff) = mean(x1 - x2) t = -1.9743 Ho: mean(diff) = 0 degrees of freedom = 7