v-vo [adt 为常数时 v-vo =at (1) 又 dx y →dk=vdt dt k=vh即x-x,=dh 为常数时 x-x=∫+am)d ∴.x-x=1+at(2) (1)、(2)消去t得 v2-V=2a(x-x)  − = t v v adt 0 0 a为常数时 v −v = at 0 (1) 又 dt dx v = dx = vdt    = x t x dx vdt 0 0 即  − = t x x vdt 0 0 a为常数时  − = + t x x v at dt 0 0 0 ( ) 2 0 0 2 1 x − x = v t + at (2) (1)、(2)消去t 得 2 ( )0 2 0 2 v − v = a x − x