④计算各效面积 4=D1=9649×2326100 3600=271m2 2840×8.1 W=5400×232×100 3600 =151m2 1700×13.6 s42y;6042×2326×1000 169m K 1135×20.3 各效面积不等,重新分配有效温度差 A,△t1+A,Mt,+A2△ △t 271×8.1+151×13.6+169×20.3 183m A 271×8.1 183 A,△t,151×13.6 =112℃ 183 A3△t3169×20 18.8℃ 183 ⑤重算各效温度: T}=52℃ t3=T+△3=52+38=90℃ T3=t3+Mt3=90+18.8=1088℃ T2=1088 t2=T2+△2=1088+12+1=1218℃ 12=t2+M2=1218+112=133℃ T=1+M1=140+12=152℃④计算各效面积： 2 3 3 2 2 3 2 2 2 1 1 2 2 1 1 1 1 1 169 1135 20.3 3600 1000 6042 2326 151 1700 13.6 3600 1000 5400 2326 271 2840 8.1 3600 1000 9649 2326 m K t W A m K t W A m K t D A =    =   = =    =   = =    =  =    各效面积不等，重新分配有效温度差： C A A t t m t A t A t A t A 1 1 0 1 2 1 1 2 2 3 3 12.0 183 271 8.1 183 42 271 8.1 151 13.6 169 20.3 =  =    = =  +  +  =   +  +  =  11.2 183 2 2 151 13.6 2 =  =    = A A t t ℃ 18.8 183 3 3 169 20.3 3 =  =    = A A t t ℃ ⑤重算各效温度： T3  = 52 ℃ t 3 = T3 + 3 = 52+ 38 = 90 ℃ T3 = t 3 + t 3 = 90+18.8 =108.8 ℃ T2  =108.8 ℃ t 2 = T2  + 2 =108.8+12+1=121.8 ℃ T2 = t 2 + t 2 =121.8+11.2 =133 ℃ T1  =133 ℃ t 1 = T1 + 1 =133+ 6 +1=140 ℃ T1 = t 1 + t 1 =140+12 =152 ℃