⑩天掌 Teaching Plan on Advanced Mathematics 例1作函数f(x) 4(x+1) 2 2的图形 解D:x≠0,非奇非偶函数,且无对称性 ∫(x)=-4x+2,f"(x)= 4(x+ 令∫(x)=0,得驻点x=-2, 令∫"(x)=0,得特殊点x=-3 imf(x)=im/(x+1)-2=-2, x→0 x→0 得水平渐近线y=-2; 2004-4-10Tianjin Polytechnic University Teaching Plan on Advanced Mathematics 例1 2 . 4( 1) ( ) 作函数 2 − 的图形 + = x x f x 解 D : x  0, 非奇非偶函数,且无对称性. , 4( 2) ( ) 3 x x f x +  = − . 8( 3) ( ) 4 x x f x +  = 令 f (x) = 0, 得驻点 x = −2, 令 f (x) = 0, 得特殊点x = −3. 2] 4( 1) lim ( ) lim[ 2 − + = → → x x f x x x = −2, 得水平渐近线 y = −2; 2004-4-10