(4)计量点后 ·溶液中c(C)决定于过量AgNO3的量，当滴入 AgNO3溶液20.02mL时 (Ag)=V(AgNO)-V(NaCDk(AgNO,) V(NaCl)+V(AgNO:) c(C)=Kpdga/c(Ag) c(Ag)=5.00×105mol/L pC1=pKm-pAg=9.74-4.30=5.44• （4） 计量点后 • 溶液中c(Cl- )决定于过量AgNO3的量, 当滴入 AgNO3溶液20.02mL时   ( ) ( ) ( ) ( ) ( ) ( ) 3 3 3 V NaCl V AgNO V AgNO V NaCl c AgNO c Ag + − = + ( ) ( ) , − + c Cl = Ksp AgCl c Ag 5 ( ) 5.00 10 / 9.74 4.30 5.44 sp c Ag mol L pCl pK pAg + − =  = − = − =