6-6循环过程卡诺循环 第六章热力学基础 212 =Cy.mT 223 =2Cp.mTi P P2 234=-2Cv,mT QaI=Cp.m(Ti-Ta)=-Cp.mTi Q=Q12+223 CrmT+2CpmT V V4 V Cp.m Cr.m+R W=(p2-p)(W4-V)=p1V1=RT1 91-22=W R了 1(3Cv.m+2R) =15.3% 6 - 6 循环过程 卡诺循环 第六章热力学基础 (3 m 2 ) 1 , 1 T C R RT V + = Q W Q Q Q 1 1 1 2 = −  = = 15.3% Cp,m = CV ,m + R ( )( ) 2 1 V4 V1 W = p − p − = p1V1=RT1 Q1 = Q12 + Q23 41 ,m 1 4 ,m 1 Q = Cp (T −T ) = −Cp T = CV ,m T1 + 2Cp,m T1 1 4 V1 V4 2 3 1 p 2 p P o V Q12 Q34 Q41 Q23 Q12 = CV ,m T1 23 ,m 1 Q = 2Cp T Q34 = −2CV ,m T1