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n =34T()+[332*2-45+3*2*2-15+2]n15 n=2k3kT(1)+[3-1*2-(k115+…+3*2-15+30*20*2*n15 k,1*(1 1-3*2 0.06 0.06 换底n2+ 0.03 P15例11的直接展开 T =2T +nlog, n=22T.+2n*log, n-n 2T+/22*log, (n/2)]+2nlog, n-n =2Tn+3nlog2 n-2n-n 2[2T+6-1og21+3nlog,n-2n-n T1+klog2n+[(k-1)+(k-2)+…+3+2+1]hn=3 3 T( 3 2 n )+(3 2 3 *2* 2 - +3*2*2 -1.5 +2)n 1.5 = n 1.5 [3T( 4 2 n )+2( 3 2 n ) 1.5 ]+(3 2 3 *2* 2 - +3*2*2 -1.5 +2)n 1.5 =3 4 T( 4 2 n )+[3 3 2*2 -4.5 +3*2*2 -1.5 +2] n1.5 … k n = 2 3 k T(1)+[3 1 ( 1)*1.5 *2 k - - k - +…+3*2 -1.5 +3 0 *2 0 ]*2* n1.5 =3 k + * 2* 1 3* 2 1*(1 3 * 2 ) 1.5 1.5 - - - - k k n 1.5 =3 k + * 2 * 1 2 3 3 * 2 1 1.5 1.5 - - k - k n 1.5 =3 k + * 2* 0.06 3 *(2 ) 1 1.5 - k k - n 1.5 =3log 2 n + 1.5 log 1.5 * 2* 0.06 3 * 1 2 n n n - - 换底n log 2 3 + 0.03 log2 -1.5 n - n n »34 nlog 2 3 -33 n1.5 =>T(n) =O( nlog 2 3 ) 注:3 log 2 n =3 log 2 log 3 3 n =(3 log 3 n) log 2 1 3 =n log 2 1 3 =n log 2 log 3 3 3 = n log 2 3 P15 例 11 的直接展开: T n =2T 2 n +nlog 2 n=2 2 T 2 2 n +2n*log 2 n-n =2 3 T 3 2 n +n/2 2 *log 2 (n/2)]+2nlog 2 n-n =2 3 T 3 2 n +3nlog 2 n-2n-n =2 3 [2T 4 2 n + 3 2 3 2 log 2 n n ]+3nlog 2 n-2n-n =2 4 T 4 2 n +4nlog 2 n-3n-2n-n 2 n k = 2 k T1 +{klog 2 n+[(k-1)+(k-2)+…+3+2+1]}n
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