02+2H20+4e=40Hp°02/oH=0.401V Po2=po CoH-=1.0 02+4H++4e=4H20 0°O2/H0=? po2=p°CH+=1.0 与pO2/OH相关 Po p021H0=p0210H=φ0210H+005921g 4 4 (coH=1014) =0,.401+00592×4×lg10 4 =0.401+0.829 =1.230O2+2H2O+4e＝4OH－  øO2 /OH －＝0.401V pO2=po cOH-=1.0 O2+4H++4e＝4H2O  øO2 /H2O＝? pO2=po cH+=1.0 与 O2 /OH －相关  øO2 /H2O＝  O2 /OH －＝  øO2 /OH －+ (cOH-=10-14) =0.401+ =0.401+0.829 =1.230 4 2 lg 4 0.0592 − OH o p po c 1 4 10 1 4 0.05924lg −