例2设a1=(110),a2=(01n),a3=(340) 31 求aF,3(aB)=(a1a2a3)2-1 解(a)=(3a1+2a2-a3a1-a2+a 0 3 a=3a1+2a2-a3=31|+21-14 012 (012) 0 3 B=ax1-a2+a3=11-11+14|=4 44例２ ( ) 1 1 1 0 T 设  = ， ( ) 3 340 T 2 (0 1 1)  = T  = ， ( ) ( 1 2 3 ) 3 1 , , 2 1 . 1 1             = −       − 求 解 (        ) = + − − + (3 2 1 2 3 1 2 3 ) (4 4 1 . ) T = − 1 2 3     = + − 3 2 1 0 3 3 1 2 1 1 4 0 1 0             = + −             (0 1 2 . )       T =     = − + 1 2 3 0 1 2     =       1 0 3 1 1 1 1 1 4 0 1 0             = − +                   4 4 1     =       −