1.1 The element carbon has atomic number 6, and so it has a total of six electrons. Two of these elec- tr rons are in the Is level. The four electrons in the 2s and 2p levels (the valence shell) are the valence electrons. Carbon has four valence electrons 1.2 Electron configurations of elements are derived by applying the following principles:

4.1 There are four C. H, alkyl groups, and so there are four C. H, CI alkyl chlorides. Each may be named by both the functional class and substitutive methods. The functional class name uses the name of the alkyl group followed by the halide as a second word. The substitutive name modifies the name of the corresponding alkane to show the location of the halogen atom

SOLUTIONS TO TEXT PROBLEMS 6.1 Catalytic hydrogenation converts an alkene to an alkane having the same carbon skeleton. Since 2-methylbutane is the product of hydrogenation, all three alkenes must have a four-carbon chain with a one-carbon branch. The three alkenes are therefore:

SOLUTIONS TO TEXT PROBLEMS 7.1 (c)Carbon-2 is a stereogenic center in 1-bromo-2-methylbutane, as it has four different substituents: H, CH, CH,CH2, and BrCH2. H BrCH2-C-CH2CH, CH3 (d) There are no stereogenic centers in2-romo-2- me. Br CH:-C-CH,CH3 CH, 7.(b) Carbon-2 is a stereogenic center in 1, 1, 2-trimethylcyclobutane

The triacylglycerol shown in text Figure 26.2a, with an oleyl group at C-2 of the glycerol unit and two ste earyl groups at C-I and C-3, yields stearic and oleic acids in a 2 I molar ratio on hydrolysis. A constitutionally isomeric structure in which the oleyl group is attached to C-1 of glycerol would yield the same hydrolysis products

The positive charge is shared equally by the three carbons indicated. Thus the two carbons ortho to the sp. e sp-hybridized carbon and the one para to it each bear one third of a positive charge (+0.33). None of the other carbons is charged. The resonance picture and the simple MO treatment agree with respect to the distribution of charge in cyclohexadienyl cation

SOLUTIONS TO TEXT PROBLEMS 13.1 The field strength of an NMR spectrometer magnet and the frequency of electromagnetic radia he Ire tion used to observe an NMR spectrum are directly proportional. Thus, the ratio 4.7 T/200 MHz is the same as 1.41/60 MHz. The magnetic field strength of a 60-MHz NMR spectrometer is

SOLUTIONS TO TEXT PROBLEMS 24.(b) A benzyl group(C., CH2) is ortho to the phenolic hydroxyl group in o-benzylphenol. OH CH2C.Hs (c)Naphthalene is numbered as shown. 3-Nitro-I-naphth has a hydroxyl group at C-1 and a nitro group

22.2 N,N-Dimethylcycloheptylamine may also be named as a dimethyl derivative of cycloheptanamine. -N(CH3)2 N,N-Dimethylcycloheptanamine 22.3 Three substituents are attached to the nitrogen atom; the amine is tertiary. In alphabetical order, the s substituents present on the aniline nucleus are ethyl, isopropyl, and methyl. Their positions are

20.1 () Carboxylic aci id anhydrides bear two acyl groups on oxygen, as in RCOCR. They are named as derivatives of carboxylic acids. Q CH:CH2CHCOH CH,CH,CHCOCCHCH_CH3 C6H C. C. 2-Phenylbutanoic acid 2-Phenylbutanoic anhydride (c) Butyl 2-phenylbutanoate is the butyl ester of 2-phenylbutanoic acid. CH,CH,CHCOCH,CH,CH2CH