7.3增量总和(△-)调制 1.简单增量调制的缺陷临界过载条件:f△=Ax与信号频率有关;信号频率越高,越容易产生过载; 2.增量总和(△-)△M基本原理编码时,对信号作“积分”变换:A(a)>A()/jo临界过载条件:(A(a)/jo)->A(a),仅由信号幅度确定,与信号频率“无关”解码时,对信号作相反的(“微分”)变换,恢复原信号

Conjugated unsaturated systems have a p orbital on a carbon adjacent to a double bond The p orbital can come from another double or triple bond The p orbital may be the empty p orbital of a carbocation or a p orbital with a single electron in it (a radical)

1.证明a(t)是常向量的充要条件是a(t)=0 2.证明()x()()x()+i()x 4.设向量函数a(t)满足a(t)a'=0,a(t)xa=0,证明a()是常向量。 5.证明F(t)=(2t-1,t2-2,-t2+4t)为共面向量函数

Recently I wrote about 10 qualities of a good employee, which prompted quite a few people to ask about the attributes of a good manager. There isn’t a magic formula for good management, of course, but if you’re a manager, perhaps these tips will help you be more effective. 1. Choose a field thoughtfully. Make it one you enjoy. It’s hard to be

一、判断题 1两共线矢量a与b的矢性积的模等于以与b为边所构成的 平行四边形的面积() 2两矢量a与b共线的充要条件是axb=0() 3矢量a{X1,F,Z}与b{X2,H2,Z2}相互垂直的充要条件是 x1X2+YY2+2122=0() 4两矢量a与b相互垂直的充要条件是a·b=0() 5矢性积是反交换的,即a×b=-(b×a)()

2008年4月笔试试卷参考答案 一、选择题 (1)C)(2)A)(3)B)(4)B)(5)A)(6)D)(7)B)(8)C) (9)D)(10)C)(11)D)(12)D(13)B)(14)C)(15)D)(16)B) (17)B)(18)A)(19)B)(20)A)(1)C)(22)B)(23)A)(24)C) (25)B)(26)C)(27)D)(28)B)(9)A)(30)C)(31)C)(32)D) (33)C)(34)D)(35)A)

1线性空间的定义 设V是一个非空集合,R为实数域如果对于任 意两个元素a,B∈V,总有唯一的一个元素∈V与 之对应称为a与的和记作y=a+又对于任 数∈R与任一元素a∈V,总有唯一的一个元素 δ∈V与之对应称为与a的积,记作δ=λa;并且这 两种运算满足以下八条运算规律(设a,,y∈V;

在数的运算中,当数a≠0时,有 aa'==, 其中a=1为a的倒数,(或称a的逆); a 在矩阵的运算中,单位阵E相当于数的乘法运算中 的1,那么,对于矩阵A,如果存在一个矩阵A

1 Equivalence Relations 【Definition】A relation R is defined on a set S if for every pair of elements (a, b), a, b S, a R b is either true or false. If a R b is true, then we say that a is related to b

一、选择题 A型题 1.a2.c3.b4.c5.a6.b7.e8.b9.c10.d11.a 12.d13.d14.d15.c16.c17.a18.d19.b20.b21.d 22.D23.D24.E25.D26.C27.b28.d29.c30.a31.c