1 分离对象: 液液混合物 – 相对挥发度等于或者接近1 (烷烃/芳烃) – 重组分 含量少,轻组分含量多(水-HAc)(含酚 废水处理) 2 两相的产生 – 混合物 + 溶剂 (分离剂) = 萃取相 + 萃余相

pH of a buffer and buffer capacity Example: For a buffer solution consisting of 0. 1 M acetic acid and o1M sodium acetate the ph of the solution is 4.75 HAc= i If an amount of hydrochloric acid equivalent to 10% of the acetate present, is added to the buffer, what is the new pH of the solution?

《分析化学》考试试卷答案 一、填空题: 1.(1)H++3po4=oh+inh3+hpo4+2p41 (2)[H']+[HAc]-[H2BO3 ]+[OH] 2不变,减小 3误差;偏差 4.1.926.22

第一节质粒载体(plasimid vectors) 第二节噬菌体载体(phage vectors) 第三节柯斯质粒载体(cosmid vectors) 第四节人工染色体载体(B/Y/HAC)