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MASSACHVSETTS INSTITVTE OF TECHNOLOGY Depart ment of Electrical Engineering and Computer Science 01-Structure and Interpret at ion of Computer Programs Spring Semester, 2005 Quiz it Closed book two sheets of not es Throug hout this quiz, we have set aside space in which you should write your answers. Please try
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6.001 Structure and Interpretation of Computer Programs. Copyright o 2004 by Massachusetts Institute of Technology 6.001 Notes: Section 10.1 Slide 1o.1.1 Table: a set of bindings Over the past few lectures, we have introduced the concepts of data abstractions, types and aggregate structures. In this lecture
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NUMERICAL SoL°To ·G川EN舟c。 MPLEX SET of0 YNAMICS 义(t)=斤(x,x) WHERE f()CouL0BE升MNLE升 R FUNCTI0N 工TCNB.工 MOss8 LE To ACTVALLY SoLVE FoR×(t)∈ ACTLY →0 EVELoP A则 UMERICAL SOLUTION. cA小NE0co0 ES TO HELP v5 D。TwsτN MATLAB BUT LET US CONSIDER THE BAsIcs
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a weakness of hashing Problem: For any hash function h, a set of keys exists that can cause the average access time of a hash table to skyrocket An adversary can pick all keys from tkeU: h(k)=i for some slot i IDEA Choose the hash function at random independently of the keys
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Balanced search trees Balanced search tree a search-tree data structure for which a height of o(g n)is guaranteed when implementing a dynamic set of n items
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Ch. 22 Unit root in Vector Time series 1 Multivariate Wiener Processes and multivari- ate FCLT Section 2.1 of Chapter 21 described univariate standard Brownian motion W(r) as a scalar continuous-time process(W: rE0, 1-R). The variable W(r) has a N(O, r)distribution across realization, and for any given realization, w(r) is continuous function of the date r with independent increments. If a set of k such independent processes, denoted
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主要内容 2.1Java语言的特点 2.1.1简单的面向对象程序设计语言 2.1.2健壮安全的分布式语言 2.1.3结构中立、可移植性强的解释型语言 2.1.4高效能 2.1.5支持多线程的动态语言 2.1.6Java与几种常用语言的比较 2.2Java执行环境 2.2.1VM机制Java平台的基础 2.2.2自动垃圾收集 2.2.3保护域机制与沙箱模型 2.2.4类加载器一一启动引擎的点火器 2.3JDK的组成与安装设置 2.3.1Java平台的组成结构 2.3.2 SET PATHSET和 CLASSPATH的作用 2.4典型例子及常见问题 2.4.1编译器、解释器、小程序观察器和反编译器 2.4.2最简单的例子 2.4.3应用程序的主方法 2.4.4小程序的运行
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Information content of a random variable Random variable x Outcome of a random experiment Discrete R V takes on values from a finite set of possible outcomes PMF: P(X=y)=Py) How much information is contained in the event X=y? Will the sun rise today Revealing the outcome of this experiment provides no information Will the Celtics win the NBa championship? Since this is unlikely, revealing yes provides more information than revealing Events that are less likely contain more information than likely events
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1.指令用法 (1)SET(置位):置位指令 (2)RST(复位):复位指令 用于各继电器Y、S和M等,置位和复位,还可在用户程序的任何地方对某个状态或事件设置或清除标志
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实验11参考答案 一、 SET TALK OFF CLEAR USE XSDA. DBF ACCEPT请输入待查学生姓名:”TO NAME LOCATE FOR姓名=NAME IF FOUNDO
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