NOTE: On the“ ethics” of problem sets Some of the theoretical exercise I will assign are actually well-known results; in other cases you may be able to find the answer in the literature. This is certainly the case for the current My position on this issue is that, basically, if you look up the answer somewhere it's your problem. After all, you can buy answer keys to most textbooks. The fact is, you will not have access to such, ehm, supporting material when you take your generals, or, in a more

Introduction Signaling games are used to model the following situation: Player 1, the Sender, receives some private information and sends a message m E M to Player 2, the Receiver. The latter, in turn, observes m but not 0, and chooses response r E R. Players'payoffs depend on 0, m and r. What could be simpler? Yet, there is a huge number of economically interesting games that fit nicely within this framework: Spence's job market signaling model is the leading example, but applications abound in IO (limit pricing, disclosure...) finance (security design) and political economics

3.1已知理想采样开关的采样周期为T秒,连续信号为下列函数,求采样的输出信号f(t) 及其拉氏变换F(s)

什么是地理信息系统—GIS ❑ GIS的概念框架 GIS的定义、理解和框架体系结构 ❑ GIS的基本内容 GIS技术涉及的基本内容 ❑ GIS的组成 硬件、软件、空间数据、管理人员 ❑ GIS的功能 基本要求、具体功能：数据采集、传输、管理和应用 ❑ GIS的特性与相关学科 GIS的学科树、GIS与相关系统区别和联系 ❑ GIS的应用领域 GIS应用与3S集成技术

回顾上一讲的内容,如果系统G(s)的输入信号是幅值为A的稳定 正弦信号,则 稳态输出信号是幅值为A·M(a)、相移为叭(a)的正弦信号 其中 现在让我们暂停一下,来考虑关于G(o)的一些说明

考虑如下的实验,该实验中稳定的线性系统由正弦输入信号驱 动。 该输入信号的拉普拉斯变换为 如果G(s)是系统的传递函数,则输出量的拉普拉斯变换为

状态空间模型的一种特殊情况是零、极点数目相同。例如,已知 回顾我们首先将G(s)分解成两部分 第一个传递函数表征输入r与中间输出量x之间的关系 在时域内,这即是微分方程

Since the mid-1980s there has been a considerable increase in legislation defining maximum temperatures during the production, distribution and retailing of chilled food. However, as soon as the food is purchased by the consumer, it is outside of any of these legislative requirements. Increasingly food poisoning incidents have been found to be due to mishandling of food in the home with insufficient refrigeration or cooling being the most fre

2.1网络通信协议 2.2网络通信的分层结构 2.30S参考模型 2.4网络的拓扑结构 2.5访问控制方法

1解: 0.05eV 查S的E=12eV,AED=E-ED 0.29eV ED-EF=EC-E (EF-E) Egl. 12eV E-E 0.29-0.05=0.22e