西业2量学 §3.6.4 动态误差数法(2) (1)动态误差系数法解决问题的思路 Φ(ssE(s) Φ2(0)+Φ2(0)s+Φ(0)s2+…+D(0)s2+ R(S) (0)i=0,1,2 =Ca+C+C,s2+…=罗C,s2 E(S)=(S).R(S) COR(S)+CSR(S)+C2S R(S)+.+CSR(S)+ e,()=Cr()+C;r()+C2r()+…+Cr()+…=∑Cro()§3.6.4 动态误差系数法(2) (1) 动态误差系数法解决问题的思路 e = = e +  e +  e  ++ e i s i + i s s R s E s s Φ (0) ! 1 Φ (0) 2! 1 Φ (0) 1! 1 Φ (0) ( ) ( ) Φ ( ) 2 ( ) Φ (0) 0, 1, 2, ! 1 ( ) = i = i C i i e i i i C C s C s C s  = = + + + = 0 2 0 1 2  E(s) Φ (s).R(s) = e ( ) ( ) ( ) ( ) ( ) ( ) ( ) 0 ( ) 0 1 2 e t C r t C r t C r t C r t C r t i i i i s i   = = +  +  ++ += = C0 R(s) + C1 sR(s) + C2 s 2 R(s) ++ Ci s i R(s) +