f((z) (-1)-(k-1) k=1,2, + Z f()(0)(-1) k=1,2 而f(0)=0 1) 2<1(公式) k=1 2将(+y=-支在点 z=0展开成T级数 解:支点为z=0,-1( )( ) ( ) ( ) ( ) , 1,2 ,K 1 1 1 ! 1 = + - - = - k z k f z k k k ( )( ) ( ) , 1,2 ,K 1 ! 0 1 = - \ = = - k k k f a k k k 而f (0 ) = 0 ( ) ( ) 1(公式 ) 1 ln 1 1 1 < - + = å ¥ = - z z k z k k k ( ) 2.将 z +1 = e aLn(1+z)的一支e aLn(1+z)在点 a z = 0展开成T级数 解 : 支点为 z = 0,-1