1利用复化梯形公式n-4)求积分V+xx 复化梯形公式fw=[/@)+25fx)+o)其中步=a 解:fx)=V1+x,a=0,b=1h=b-0=1- =025 n 4 (n为区间的等分个数 f(a)=f(0)=1:f(x)=f(0.25)=1.03078 f(x)=f0.5)=1.11803f(x)=f0.75)=1.25 f(b)=f(1)=1.41421: +F=[f@)+2空fx)+fo -025+2×003078+11803+12)+14142-1151481. ( 4) 1 . 1 0 2 利用复化梯形公式n = 求积分 + x dx n b a f a f x f b h h f x dx N k k b a − = = + + − = 复化梯形公式: ,其中步长 1 1 ( ) 2 ( ) ( ) 2 ( ) ( ) 0.25 4 1 0 ( ) 1 , 0, 1, 2 为区间的等分个数 解 : n n b a f x x a b h = − = − = + = = = ; ; ; ; ; ( ) (1) 1.41421 ( ) (0.5) 1.11803 ( ) (0.75) 1.25 ( ) (0) 1 ( ) (0.25) 1.03078 2 3 1 = = = = = = = = = = f b f f x f f x f f a f f x f 1 2 (1.03078 1.11803 1.25) 1.41421 1.15148 2 0.25 ( ) 2 ( ) ( ) 2 1 1 1 1 0 2 = + + + + = + = + + − = f a f x f b h x dx n i i