3x1+2x2+4x3至42 3x1+2x2≤30 0三x1,0至x2,0x First, enter the coefficients f=[-5;-4;-6] [1-11 324 b=[20,42;30 Next, call a linear programming routine xlp(f, A, b, Ib) Entering 0.0000 15 实际此命令改为 x=linprog(f, A, b, Aeq, beg) x=linprog(f, A, b, Aeq, beq, Ib, ub) 对以上的问题可做如下的操作 First enter the coefficients. [1 b=[20,42,30; zeros(3, 1) Next, call a linear programming routine [x, fval, exitflag, output, lambda]=linprog(f, A, b, l,0.Ib); Entering x, fval, lambda. ineqlin, and lambda. lower gets 0.0000 15.0000 3.0000subject to x1-x2+x3≦20 3x1+2x2+4x3≦42 3x1+2x2≦30 0≦x1, 0≦x2,0≦x3 First, enter the coefficients: f = [-5; -4; -6] A = [1 -1 1 3 2 4 3 2 0]; b = [20; 42; 30]; lb = zeros(3,1); Next, call a linear programming routine: x= lp(f,A,b,lb); Entering x x = 0.0000 15.0000 3.0000 实际此命令改为： x = linprog(f,A,b,Aeq,beq) x = linprog(f,A,b,Aeq,beq,lb,ub) 对以上的问题可做如下的操作： First, enter the coefficients: f = [-5; -4; -6] A = [1 -1 1 3 2 4 3 2 0]; b = [20; 42; 30]; lb = zeros(3,1); Next, call a linear programming routine: [x,fval,exitflag,output,lambda] = linprog(f,A,b,[],[],lb)； Entering x, fval,lambda.ineqlin, and lambda.lower gets x = 0.0000 15.0000 3.0000