解法一:先正交化,再单位化 (1)取B1=a1 (2)令B2=kB1+a2,使得B2与B正交 a2B2]=Ha1,B1]+[a1,a2]=0 k 故月2=(%-%10) a1,B1]2 (3)令63=kB+k2B2+a3,且B3与B2,月1正交 得=_LB,3] k B2a2]_1 B1,B1]2 B2,B2]31 1 2 1 2 2 1 1 2 1 1 1 2 1 2 T 1 1 2 2 2 1 1 3 1 1 2 2 3 3 2 1 1 3 2 2 1 2 1 1 2 2 (1) (2) , , [ , ] [ , ] [ ] 0, [ ] 1 , ( 1 0) [ ] 2 (3) , , , [ , ] 1 1 [ , ] , , [ , ] 2 [ , ] 3 k k k k k k k                                  = = + = + =  = − = − = − = + + = − = = − = 先正交化，再单位化 取 令 使得 与 正交 , , 故 , 令 且 法一： 与 解 正交 得