⑩天掌 Teaching Plan on Advanced Mathematics (1)分割T=t0<1<t2<…<tn1<tn=T2 ≈v(;)A 部分路程值 某时刻的速度 (2)求和s≈∑v7)△M (3)取极限λ=max{△千,△ 29 路程的精确值S=im∑v(τ) 况→)0 「返回 Tianjin Polytechnic Moiwendity wTianjin Polytechnic University Teaching Plan on Advanced Mathematics （1）分割 1 0 1 2 1 T2 T t t t t t =    n−  n =  i = i − i−1 t t t i i i s  v( )t 部分路程值 某时刻的速度 （2）求和 i i n i s  v t = ( ) 1  （3）取极限 max{ , , , } 1 2 n  = t t  t i n i i s = v t = → lim ( ) 1 0  路程的精确值  返回