由上述差商表对角线上取得的值 f(x)=0,f f[x,x2x]=2,fx0,x1,x2,x3]=1 则牛顿三次插值多项式为 N(x)=0-5(x-1)(x-2)(x-3)+2(x-1)(x-2) +(x x x3-4x+3由上述差商表对角线上取得的值 则牛顿三次插值多项式为 ( 0 0 1 ) 0 1 2 0 1 2 3 0, [ , ] 5, [ , , ] 2, [ , , , ] 1, f x f x x f x x x f x x x x = = − = = ( ) ( )( )( ) ( )( ) ( )( )( ) 3 0 5 1 2 3 2 1 2 1 2 3 4 3. N x x x x x x n x x x x x = − − − − + − − + − − − = − +