tanx-sin x (4)im tanx-sinx X-x 注意:lin m ≠lim x→>0 3 x→0x sInr tanx-sinx 1) 解 lim =lm cosr x→0 SInx cosx lim x r cos x =lim sine =lim sinx 1 0r x cos x →0x2cosx sInd lim lim y0 x x- 0 2 x 214 3 0 tan sin (4).lim ; x x x → x − 3 3 0 0 tan sin lim lim . x x x x x x → → x x − − 注意: 3 3 0 0 2 0 1 sin ( 1) tan sin cos lim lim sin (1 cos ) lim cos x x x x x x x x x x x x x x → → → − − = − = 解 2 2 0 0 sin sin 1 2 lim lim x x cos 2cos x x x → → x x x x x = = 0 0 sin 1 1 lim lim x x 2cos 2 x → → x x = =