Shanghai Jiao Tong University 1.劳斯判据：例1 特征方程：S4+2s3+3s2+4s+5=0 1 3 5 23-=1 2 4 0 2×5-0 二 2 5 2 >>roots([12345]) s 1x4-2x5 1 0.2878+1.4161i 0.2878-1.4161i -1.2878+0.8579i 5 -1.2878-0.8579iShanghai Jiao Tong University 1. 劳斯判据：例1 1. 劳斯判据：例1 s 2s 3s 4s 5 0 4 3 2 + + + + = s 1 5 2 2 5-0 2 2 2 3-4 = = × × s 6 0 1 1 1 4-2 5 = − × × s 5 0 s 2 4 0 s 1 3 5 3 4 >> roots([1 2 3 4 5]) 0.2878 + 1.4161i 0.2878 ‐ 1.4161i ‐1.2878 + 0.8579i ‐1.2878 ‐ 0.8579i 特征方程：