二小结:1设f(x)=a1x+a1x +∴+a 则有 n lim f(x)=ao(lim x)"+a,(lim x)+.+a x→x x→x0 x→x =a n-1 roar 0~0 1~0 +an=f(xo) 2设∫(x)= P(x) 且Q (x0)≠0, 0 则有 e(r) lim f(x)=.0 lim P(x) P(xo) =f(x0) lim o(x) (o) x→>x0 若Q(x)=0,则商的法则不能应用 上页小结: 1.设 f (x) = a0 x n + a1 x n−1 ++ an ,则有n n x x n x x x x f x = a x + a x + + a − → → → lim ( ) 0 ( lim ) 1 ( lim ) 1  0 0 0 n n n = a x + a x + + a −  1 0 0 1 0 ( ). x0 = f 设 , 且 ( ) 0, 则有 ( ) ( ) 2. ( ) = Q x0  Q x P x f x lim ( ) lim ( ) lim ( ) 0 0 0 Q x P x f x x x x x x x → → → = ( ) ( ) 0 0 Q x P x = ( ). x0 = f ( ) 0, . 若Q x0 = 则商的法则不能应用