设n>m F(S) N(S)bmSm+bm-iSm-1+...+biS+bo DS)anSm+an-Sm-l+··+a1S+ao 令D(S)=anSm+am-S-1+.+a1S+a=0可得根为 P1>P22....Pn (1)D(S)有n个实数单根 K K -￡IES含Ke时F(S)= S –p1 K1 S –p2 K2 S –pi Ki S –pn Kn + + • • • + + • • • + f(t)= £–1[F(S)]= ¦ Ki e pi t i=1 n N(S) D(S) F (S)= bmS m + bm–1S m–1 + + b1S + b0 • • • anS n + an–1S n–1 + + a1S + a0 ••• = 䇮n>m ԔD(s)=anS n + an–1S n–1 + … + a1S + a0=0ਟᗇṩѪ p1 , p2 ,…, pn ˄1˅ D(S)ᴹnњᇎᮠঅṩ