再单位化07β0n2V6°B1=(n3Bβ4 =(5,-,-2′n4Bn1,n2,3,n4即为所求69.2标准正交基§9.2 标准正交基 1 1 1 1 | |    = 2 2 2 1 | |    = 再单位化 3 3 3 1 | |    = 4 4 4 1 | |    =     1 2 3 4 ,,, 即为所求．1 1 ( , ,0,0) 2 2 = 1 1 2 ( , , ,0) 6 6 6 = − 1 1 1 3 ( , , , ) 12 12 12 12 = − 1 1 1 1 ( , , , ) 2 2 2 2 = − −