180(1+ Jo(+yo y"=180°+arcg=c-90°-arcg arcing =577°+ac1g-arc1g→o=0.78md/s G(s)= (1+1.28s(1+0.5s) (1 0s+S)(1+641+001s) G2(s)G0(s)= 180(1+1.28s) s(1+0.167s)1+64s)(1+0.0s) ⑥验算精度指标。γ"=455°,h=27B,满足要求。 图6-21滞后超前校正例6-3系统对数频率特性203 ) 100 )(1 50 )(1 6 (1 180(1 ) ( ) ( ) 0          j j j j j G j G j a a c + + + + = 100 50 6 180 90 '' '' '' '' c a c c a c arctg arctg arctg arctg         =  + −  − − − a a arctg arctg   3.5 175 = 57.7 + − → rad s a  = 0.78 / (1 64 )(1 0.01 ) (1 1.28 )(1 0.5 ) ) 100 )(1 0.78 50 (1 ) 2 )(1 0.78 (1 ( ) s s s s s s s s G s c + + + + = + + + + = (1 0.167 )(1 64 )(1 0.01 ) 180(1 1.28 ) ( ) ( ) 0 s s s s s G s G s c + + + + = 验算精度指标。   = 45.5， h = 27dB，满足要求。 10-2 10-1 100 101 102 -100 -50 0 50 100 10-2 10-1 100 101 102 -300 -200 -100 0 100 图 6-21 滞后超前校正例 6-3 系统对数频率特性