ex4.求曲面x2+y2+z22a2与z≥、x2+y 所围成的立体体积 Solution :0≤p≤√2a, 0≤qs 0≤b≤2丌, Q p sin dodge=[del doy 0 0 p sin ppap =2π4sinq (√2a 丌(√2-1)a 0 3 K心ex4. 求曲面 2 2 2 2 x + y + z  2a 与 2 2 z  x + y 所围 成的立体体积. Solution. x y z 0    2 , , 4 0      : 0    2a,   V = dxdydz =    a d d d 2 0 2 0 2 0 sin 4          =  4   0 3 3 ( 2 ) 2 sin d a ( 2 1) . 3 4 3 =  − a   =  sinddd 2