MALA q=20kN/m M-5kNm B Ax F/p E K Im m 0.5m ∑∑ F=0 F Ax =0 F.=0 F+50+(20×3)-29=0 h=8kN(个 F ∑M4=0 MA-50×103×1+5×103-20×103×4×3=0 M=96.5kN.mFx = 0 = 81kN() FAyMA = 96.5kNm M A = 0 Fy = 0 FAx = 0 − FAy + 50 + (203)− 29 = 0 50 10 1 5 10 20 10 4 3 0 3 3 3 M A −   +  −    = FBy MA FAx FAy C D K q =20kN/m Me=5kN·m A E F B 1m 0.5m 1m 3m 1m