F-50kN 920kN/m M=5kNm B AE D K Im Im 3 m m 0.5m M 5OkN ∑Mc=0 E Cx Ax =20KN/m M=5kNm D K By ∑Mc=0-(20×103×3×2.5)+5×103+F×5=0 F=29KNMC = 0 MC = 0 FCx FCy A C E 50kN FCy ' FCx ' MA FAx FAy 1m 0.5m 1m 3m 1m B A E C D K F=50kN q=20kN/m Me=5kN·m D K q =20kN/m C FBy Me=5kN·m FBy = 29kN (20 10 3 2.5) 5 10 5 0 3 3 −    +  + FBy  =