解 sin b=1+cosx=2cos 1- sina 故f(c0)=2(1-c号 SiN 2 cos3. 1.3.3已知∫(x)=e",f[g(x)]=1-x且g(x)≥0 求g(x)及其定义域 解f[g(x)]=e)'=1-xg(x)=√n(1-x).由ln(1 x)≥0≈1一x≥1→x≤0 1.3.4设∫ x1·x≠1.求兀] f{f∫(f(x)]}. 1-x(x≠0x≠1) f2(x)=几f(x)]=-x 1 ∫(x)=/2(x)]=x f (r)=ffff(x))])= fTf(x)]=x 般地,fn(x)=x,fn1(x)=x1(m≥1) 1.3.5设 lx|<1 f(x)=〈0 x|:=1 g(r)=e' 求汇g(x)]和g[f(x)]. g(x)|<1 fg(x)]=〈0, g(x) Ig(r)I