正在加载图片...
算法2:由一个可简约的MFD求不可简约的MFD 设G(s)=N()D(s,N(s),D(s)非右互质, D(s)L「Rs) U( R(s)非单模,但非奇异 D(s) N(S/ R(S) R(S =V(S 0 (S)V2(S)R(S)V(S)R(S) 21(s)V2(s)0」[V2(s)R(s) AD(S)=V(SR(S) N(S)=VI(SR(S) 故G(s)=V2(s)V1(s是一个不可简约的右MFD算法2:由一个可简约的MFD 求不可简约的MFD ( ) ( ) ( ) . ( ) ( ) ( ), ( ) ( ) ( ) ( ) ( ) ( ) ( ) 0 ( ) ( ) ( ) ( ) ( ) 0 ( ) ( ) 0 ( ) ( ) ( ) ( ) , ( ) , 0 ( ) ( ) ( ) ( ) ( ) ( ) ( ), ( ), ( ) , 1 2 1 1 1 1 1 2 1 2 1 1 1 2 1 2 2 1 1 1 2 1 1 G s V s V s MFD D s V s R s N s V s R s V s R s R s V s R s V s V s V s V s R s V s R s U s N s D s R s R s N s D s U s G s N s D s N s D s 故 是一个不可简约的右 有 非单模 但非奇异 设 非右互质 − − − = = =       =            =       =       =             =      =
<<向上翻页向下翻页>>
©2008-现在 cucdc.com 高等教育资讯网 版权所有