(1+√5)「A 2 同理可得 (1-√5)-A)X=0 个基础解系是 (1-√5)2 21 1 1 (1 5) 2 1 1     +   = =           同理可得 1 ( (1 5) ) 0 2 − − = I A X 一个基础解系是 2 2 1 (1 5) 2 1 1     −   = =          