b1bhbabb=[a + (n-1)b]a-1bbab1bb000-ba000a-b..=[a +(n-1)b]0000a-b[a +(n -1)b](a -b)"-1S2.4行列式的性质R下§2.4 行列式的性质 1 1 [ ( 1) ] 1 1 b b b a b b a n b b a b b b a = + − 1 0 0 0 [ ( 1) ] 0 0 0 0 0 0 0 b b b a b a n b a b a b − = + − − −   1 ( 1) ( )n a n b a b − = + − −