对一阶电路求特解 zo y+a, y=A, sin(ot+)=v2Asin(ot+) 方法1 a1+(an0) a0 y=9-tan 所以 Yn=Yn∠v y,(t=Y sin(ot +o)对一阶电路求特解 0 1 sin( ) 2 sin( ) m dy a a y A t A t dt + = + = +     方法1 2 2 1 0 ( ) m m A Y a a  = + 1 0 1 tan a a    − = − 所以 Y Y m m =  ( ) sin( ) p m y t Y t = +  