此处E(MS系统间)=ETE(T)]?,(T:为各个系统的总和数) =02+no? E(MS误差)=E(e2)=o2,(e为误差) 因而 62=17.77 62+262=72.79 6=(72.79-17.77)/2=27.51 h2= 626262 27.51 =60.76% 66+66+62 27.51+17.77此处E(MS系统间)=E[Tt -E(Tt )]2 ，(Tt 为各个系统的总和数) = 2 2  + n E(MS误差)=E(e 2 )= ，(e为误差) 2  因而 ˆ 17 77 2 σ = . ˆ 2 ˆ 72 79 2 2 σ σ . + τ = ˆ (72.79 17.77) 2 27.51 2  = − = 60.76% 27.51 17.77 27.51 ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ 2 2 2 2 2 2 2 2 2 = + = + = + = =           g e g p g h