n=1时,h=b-a 则由(1)(2)(3)式,有 b f(a)+∫(b) b f(a+h 若n=21记Tn=10(k-1)k=1,2,… b b-a x =a+ih=a+ 2 b X +h=a+(j+ a+(2j+1)n = 1时，h = b - a 则由(1)(2)(3)式,有 [ ( ) ( )] 2 1 f a f b b a T + - = ) 2 1 ( 2 2 1 2 1 f a h b a T T + - = + (0) = T0 (1) = T0 ( 1) 记Tn = T0 k - 1 2 - = k 若n k = 1,2,L x a jh j = + 1 2 - - = k b a h x x h j j 2 1 2 1 = + + 1 2 ) 2 1 ( - - = + + k b a a j 1 2 - - = + k b a a j k b a a j 2 (2 1) - = + +