其中x1=x1+h=a+(+)h b 4n [f(a)+2∑f(x)+2∑f(x1)+f(b) 0 b-(a)+2/(x)+(b)+=2/(x) 0 =1r+b-2r(x)=1rn+bn/(a+(+ 0 j=0 b=a(a+(2)+1 n 2n j (3) 2n[ ( ) 2 ( ) 2 ( ) ( )] 4 1 0 2 1 1 1 2 f a f x f x f b n b a T n j j n j n + j + + - = å å - = + - = x x h a j h j j ) 2 1 ( 2 1 2 1 = + = + + + 其中 å å - = + - = - + + + - = 1 0 2 1 1 1 2 ( ) 4 [ ( ) 2 ( ) ( )] 4 n j j n j j f x n b a f a f x f b n b a å - = + - = + 1 0 2 1 ( ) 2 2 1 n j j n f x n b a T å - = + + - = + 1 0 ) ) 2 1 ( ( 2 2 1 n j n f a j h n b a T å --------(3) - = - + + - = + 1 0 ) 2 ( (2 1) 2 2 1 n j n n b a f a j n b a T