、第一类换元法 定理1设f(a)具有原函数F(n)且n=p(x)可 导,则x)(x)dx=∫(0n=F(n)ms+C =F|(x)+C 证 dFI flu du Flo(x) dx dx f(uo(x) =∫!(x)lp(x)一、第一类换元法 设f (u)具有原函数F(u),且u = (x)可 证 = f[(x)](x) ( ) F[ (x)] x x F u d d d d = ( ) x u u F u d d d d = = f (u)(x) ( ) ( ) ( ) ( ) . ( ) f x x x f u u F u C u x = = + = d d 定理1 = F[(x)] + C 导,则