结论 2 0 下三角行列式:a31a32a3 000 1122 22 nIn nn 11a12t13 0 2223 上三角行列式:00a23 nn1 …a3n=a1al2alm, 000…amn 00 0 0 22 0 对角行列式:00a3…0=a12 nn 000 nn 首页上页返回下页 结束 铃首页 上页 返回 下页 结束 铃 下三角行列式 n n n n n n n a a a a a a a a a a a a a 0 0 0 0 0 0 1 1 2 2 1 2 3 3 1 3 2 3 3 2 1 2 2 1 1 =            结论 上三角行列式 n n n n n n n a a a a a a a a a a a a a 0 0 0 0 0 0 3 3 3 1 1 2 2 2 2 2 3 2 1 1 1 2 1 3 1 =            对角行列式 n n n n a a a a a a a 0 0 0 0 0 0 0 0 0 0 0 0 3 3 1 1 2 2 2 2 1 1 =            下页