·过程后： 0.01m溶液：n-1摩尔B,5550n摩尔A, xg=(n-1)/5550n; xA=(5549n+1)/5550n ● μA=4⅓*+RTIn[(5549n+1)/5550nl 0 μs=μg*+RTIn(n-1)/5550] 0.001m溶液： n+1摩尔B, 55500n摩尔A, xg=(n+1)/55500n; x4=(55499n-1)/55500n 4a=4a+RTIn(55499n-1)/55500nl HB=uB+RTIn[(n+1)/n55500] 溶液的G为： G=5550n{u4*+RTIn[(5549n+1)/5550n} +(n-1)Hμs*+RTln[(m-1)/n5550]} +55500nkμa*+RTln[(55499n-1)/55500nl} +(n+1){ug*+RTIn(n+1)/n55500]} • 过程后: • 0.01m溶液: n-1摩尔B, 5550n摩尔A, xB=(n-1)/5550n; xA=(5549n+1)/5550n • A= A *+RTln[(5549n+1)/5550n] • B= B *+RTln[(n-1)/n5550] • 0.001m溶液: n+1摩尔B, 55500n摩尔A, xB=(n+1)/55500n; xA=(55499n-1)/55500n • A= A *+RTln[(55499n-1)/55500n] • B= B *+RTln[(n+1)/n55500] • 溶液的G为: • G=5550n{A *+RTln[(5549n+1)/5550n]} +(n-1){B *+RTln[(n-1)/n5550]} +55500n{A *+RTln [(55499n-1)/55500n]} +(n+1){B *+RTln[(n+1)/n55500]}