。过程的吉布斯自由能改变为： △G=G后-G前 =(-1)ug+RTIn[(n-1)/n5550]}-nluB+RTIn(1/5550)川 +(n+1){μg*+RTIn(n+1)/n55500]}-nlμg*+RTln(1/55500)川 +5550nμA*+RTIn[(5549n+1)/5550m}- 5550nlμ⅓*+RTn(5549/5550)l +55500n{μ⅓*+RTln[(55499n-1)/55500nl}- 55500nlμ⅓*+RTln(55499/55500)川 =(m-1)RTln[n-1)/n5550]-nRTIn(1/5550) +(n+1)RTIn[(n+1)/n55500]-nRTIn(1/55500) +5550nRTn(5549n+1)/5550nl-ln(5549/5550)} +55500nRT{n[(55499n-1)/55500n]-ln(55499/55500)} =(m-1)RTln[(n-1)/m-RTln(1/5550) +(n+1)RTIn[(n+1)/m]+RTIn(1/55500) +5550nRTn1+1/5549n] +55500 nRTIn[1-/55499n• 过程的吉布斯自由能改变为: • G=G后-G前 • =(n-1){B *+RTln[(n-1)/n5550]}－n[B *+RTln(1/5550)] +(n+1){B *+RTln[(n+1)/n55500]}－n[B *+RTln(1/55500)] +5550n{A *+RTln[(5549n+1)/5550n]}－ 5550n[A *+RTln(5549/5550)] +55500n{A *+RTln [(55499n-1)/55500n]}－ 55500n[A *+RTln(55499/55500)] • = (n-1)RTln[(n-1)/n5550]－nRTln(1/5550) +(n+1)RTln[(n+1)/n55500]－nRTln(1/55500) +5550nRT{ln[(5549n+1)/5550n]－ln(5549/5550)} +55500nRT{ln [(55499n-1)/55500n]－ln(55499/55500)} • = (n-1)RTln[(n-1)/n]－RTln(1/5550) +(n+1)RTln[(n+1)/n]+RTln(1/55500) +5550nRTln[1+1/5549n] +55500nRTln[1-/55499n]