正在加载图片...
·△G=RTIn(5550/55500) +limnRTIn[(n-1)/n]0-1 tlim→RTIn[n+1)/n]1 +limn 5550nRTIn[1+1/5549n] +limn55500nRTIn[1-/55499n] =-5707.692 +RT[-In(e)]+RTIn(e) +RTI5550/5549-55500/554991 ● =-5707.692+0.402 =-5707.3 J/mol • G = RTln(5550/55500) +limn→ RTln[(n-1)/n]n-1 +limn→ RTln[(n+1)/n]n+1 +limn→ 5550nRTln[1+1/5549n] +limn→ 55500nRTln[1-/55499n] • =-5707.692 +RT[-ln(e)]+RTln(e) +RT[5550/5549-55500/55499] • =-5707.692+0.402 • =-5707.3 J/mol
<<向上翻页向下翻页>>
©2008-现在 cucdc.com 高等教育资讯网 版权所有